Shenzhen regulator low sized printers ideal model factory price regulator

AC voltage regulator is the output apparent power (kVA) is the nominal rated capacity, and under normal circumstances is not purely resistive load, ie the power factor COS ￠ ≠ 1, the regulator can actually output active power kW = Capacity (kVA) × COS ￠. Therefore, the actual selection of rated power, power factor and load type of electrical equipment, according to the specific circumstances of a reasonable choice of power supply, the output power should leave adequate margin, especially when the impact load selection margin To more specific selection safety factor nature of the load in the table below to select the type of device safety factor of power supply capacity purely resistive load incandescent, resistance wire, electric and other equipment 1.25 to 1.5 1.25 to 1.5 times the total power load inductive, capacitive load fluorescent lamps, fans, motors, pumps, air conditioners, computers, refrigerators, etc. 2 ~ 3 ≥2 ~ 3 times the total power load inductive, capacitive load (such as motors, computer) environment, should be considered in the selection load The starting current is particularly large (up to 5-8 times the rated current), the regulator should be chosen so that the capacity is 2.5 to 3 times the load power. Such as: three-phase motor 2.2kW 1 Taiwan, 5.5 kW 1 station, the choice of the regulator, the capacity ≥ (2.2kW + 5.5 kW) × 2.5 = 19.25 kVA, that is, at least to choose more than SJW-20 kVA three-phase product stability voltage regulator.